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Consider the statement: For all integers n, if n3 is even then n is even. a. Explicitly write out what you are supposing and what you are trying to prove, if you are proving the statement by proving the contrapositive. Suppose _______________________________________________________________________ Need to show ____________________________________________________________________ b. Prove the statement by the method of the contrapositive

User Marco V
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1 Answer

1 vote

Answer:

It is proved that if
n^3 is even the n is even.

Explanation:

Given n is any integer.

To show
n^3 is even then n is even.

Proving by contrapositive suppose
n^3 is odd. Then we need to show n is odd.

Then, letting k is a ny integer,


n^3=2k+1\implies n=(2k+1)^{(1)/(3)}

Now since (2k+1) is odd therefore n is odd.

Conversly let n is odd, then,


n=2k+1\implies n^3=(2k+1)^3

since 2k+1 is odd so
n^3 is odd.

This proves, if n is even then
n^3 is even.

User Satyam Gondhale
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