Answer:
It is proved that if
is even the n is even.
Explanation:
Given n is any integer.
To show
is even then n is even.
Proving by contrapositive suppose
is odd. Then we need to show n is odd.
Then, letting k is a ny integer,
Now since (2k+1) is odd therefore n is odd.
Conversly let n is odd, then,
![n=2k+1\implies n^3=(2k+1)^3](https://img.qammunity.org/2021/formulas/mathematics/college/du6mwud0r1bcumemzb6mer67fobtvvh4m8.png)
since 2k+1 is odd so
is odd.
This proves, if n is even then
is even.