Answer:
4.75% probability that the line pressure will exceed 1000 kPa during any measurement
Explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 950, \sigma = 30](https://img.qammunity.org/2021/formulas/mathematics/college/5mpqeltoiip2qaz7ao7f7qu0gbz9ez0stc.png)
What is the probability that the line pressure will exceed 1000 kPa during any measurement
This is 1 subtracted by the pvalue of Z when X = 1000. So
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![Z = (1000 - 950)/(30)](https://img.qammunity.org/2021/formulas/mathematics/college/9071lr8cyb5yr8kxvh78u40qryyor98bih.png)
![Z = 1.67](https://img.qammunity.org/2021/formulas/mathematics/college/jz0l76bqzjw53oep499yce0womluxsqfak.png)
has a pvalue of 0.9525
1 - 0.9525 = 0.0475
4.75% probability that the line pressure will exceed 1000 kPa during any measurement