Answer:
a) 80.67%
b)1.14%
c)1.19%
d)0.05%
Step-by-step explanation:
The maximum efficiency in a heat engine is expressed as;
1-Tc/Th
where Tc=temperature of the cold 'sink
Th=temperature of the heat reservoir
Given that Tc=290 K and Th= 1500 K then;
a) thermal efficiency = 1- 290/1500 = 0.8067 =80.67%
b) Increasing TH by 5% will be 105/100 *1500 =1575 K
New thermal efficiency = 1- 290/1575 =0.8159 =81.59%
Change in thermal efficiency = 0.8159-0.8067 =0.0092
Percentage change in thermal efficiency =change in thermal efficiency/initial thermal efficiency *100
0.0092/ 0.8067 *100 = 1.14%
c) Decrease TC by 5% = 95/100 * 290 = 275.5 K
New thermal efficiency = 1-275.5/1500 = 0.8163 = 81.63%
change in thermal efficiency =0. 8163-0.8067 =0.0096
percent change in thermal efficiency =0.0096/0.8067 *100 =1.19%
d)If TH is increased by 5% , thermal efficiency is 0.8159 as in (b) above
if TC is decreased by 5% , thermal efficiency is 0.8163 as in (c) above
The change in thermal efficiency = 0.8163-0.8159 = 0.0004
percent change in thermal efficiency = 0.0004/0.8067 *100 =0.05%