Question

Follow the steps above to solve the problem: A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the normal. What was the ray's angle of incidence on the diamond

Answer 1

The ray's angle of incidence on the diamond is 65.47°

Step-by-step explanation:

Data

refractive index of water:
`n_(water) =1.33`

refractive index of diamond:
`n_(diamond ) =2.42`

We can solve it by using snell's law.

snell's law:

`n_(water) *sin(tita)_(i) =n_(diamond) *sin(tita)_(r)`

divide both side by
`n_(water)`

`sin(tita)_(i) =(n_(diamond) *sin(tita)_(r))/(n_(water) ) \\sin(tita)_(i) =(2.42*sin(30))/(1.33) \\sin(tita)_(i) =(1.21)/(1.33)`

θi
`=sin^(-1) (0.9098)`

θi
`=65.47`°