162k views
11 votes
"All rational functions have asymptotes and points of discontinuity." Katlyn wants to put this statement in her math book. Is this statement true? Explain, for her benefit, using 2 examples

User Ashigore
by
4.1k points

1 Answer

7 votes

Answer:

Not true.

Explanation:

A rational function is like P(x) / Q(x) where P and Q are polynomials.

Examples would be x^2 / (x^2 - 2) and x^2 / (x^2 + 2).

Now the first one will have a vertical asymptote at x = √2 because this value would make the denominator zero.

The second one will have no asymptotes because the only value that would make x^2 + 2 = zero is not real (it would be √2i). So the domain of this is all real numbers , and no asymptotes.

User Juha Vehnia
by
4.9k points