Question

#10 please help me solve this

Answer 1

-3/4; 4/3

Explanation:

8x - 6y = -4

6y = 8x + 4

y = (8/6)x + (4/6)

y = (4/3)x + (2/3)

Perpendicular: m1 × m2 = -1

Slope: -3/4

Parallel lines: m1 = m2

Slope: 4/3

Answer 2

Given:

Line
`8 x-6 y=-4`

To find:

Slope of the perpendicular line and slope of the parallel line.

Solution:

Equation of a given line:

`8 x-6 y=-4`

Subtract 8x on both sides, we get

`8 x-6 y-8x=-4-8x`

`-6 y=-8x-4`

Divide by -6 on both sides.

`$(-6 y)/(-6) =(-8x)/(-6) -(4)/(-6)`

`$y =(4x)/(3) +(2)/(3)`

Slope of this line is
`(4)/(3)`.

If two lines are perpendicular then their slopes are negative inverse of one another.

Slope of perpendicular line =
`-(3)/(4)`

If two lines are parallel, then their slopes are equal.

Slope of perpendicular line =
`(4)/(3)`