Answer:
The answer to your question is 6 h 20 min or 18:20
Explanation:
Data
Initial time = 4 pm
1st route = 20 min
2nd route = 35 min
Process
1.- Calculate the Least common factor (LCF)
20 35 2
10 35 2
5 35 5
1 7 7
1
LCF = 2 x 2 x 5 x 7
= 140 min
2.- Convert the minutes to hours
140 /60 = 2 hours 20 min
3.- Calculate the hour when the two buses will meet again
4 pm + 2h20 min = 6 h 20 min or 18:20