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Find c
Round to the nearest tenth

Find c Round to the nearest tenth-example-1
User Leila
by
4.5k points

2 Answers

3 votes

Answer:

4.2

Explanation:

c=√a2+b2﹣2abcosγ = √72+82﹣2·7·8·cos(32°) ≈ 4.24483

Hope this helps :)

User Marleni
by
4.2k points
5 votes

The value of c is 4 feet for the given triangle it is obtained by law of cosines formula.

Explanation:

The given is,

Triangular diagram with side dimensions

Step:1

Law of Cosines formula is,


c^(2)= a^(2)+b^(2) - 2ab cos C.......................(1)

From the given diagram,

a = 8 feet

b = 7 feet

Angle, C = 32°

Substitute the values then equation (1) becomes,


c^(2) =8^(2) +7^(2) -2(8)(7) cos 32


= 64+49-2(56)cos32


=113-(112)(cos 32)

Substitute the value of cos 32°


=113-(112)(0.848) (∵
cos32=0.848 )


= 113-(94.98)


c^(2) =18.0186

Take square root on both sides the above equation becomes,


c=√(18.0186)


=4.244

c ≅ 4 feet

Result:

The value of c is 4 feet for the given triangle it is obtained by law of cosines formula.

User Khaliah
by
5.1k points