Question

The total number of democrats and republicans in the u.S house of representatives during the 111th congress was 435. There were 31 more democrats than republicans. How many members of each party were there

Answer 1

There were 202 members of Republican party and 231 members of Democrats party.

Explanation:

Given:

The total number of democrats and republicans = 435

We need to find the members of each party.

Solution:

Let the members of republicans be 'x'.

Now Given:

There were 31 more democrats than republicans.

members of democrats =
`x+31`

Now we know that;

The total number of democrats and republicans is equal to sum of members of republicans and members of democrats.

framing in equation form we get;

`x+x+31=435\\\\2x+31=435`

Subtracting both side by 31 we get;

`2x+31-31=435-31\\\\2x=404`

Dividing both side by 2 we get;

`(2x)/(2)=(404)/(2)\\\\x=202`

members of republican part = 202

members of democrats party =
`x+31=202+31=233`

Hence There were 202 members of Republican party and 231 members of Democrats party.

Answer 2

There were members of 202 republicans and 233 democrats.

Explanation:

Given:

The total number of democrats and republicans in the U.S house of representatives during the 111th congress was 435.

There were 31 more democrats than republicans.

Now, to find the members of democrats and republicans were there.

Let the republicans be
`x.`

And the democrats =
`x+31.`

The total number of democrats and republicans = 435.

Now, to get the members of each party we solve an equation:

`(x)+(x+31)=435\\\\x+x+31=435\\\\2x+31=435`

Subtracting both sides by 31 we get:

`2x=404`

Dividing both sides by 2 we get:

`x=202.`

The number of republicans = 202.

Now, substituting the value of
`x`:

`x+31\\\\=202+31\\\\=233.`

The number of democrats = 233.

Therefore, there were members of 202 republicans and 233 democrats.