Question

abigail's 8.12 kg bowling ball is traveling at 1.7 m/s and collides with josh's 524 g beach ball that is sitting next to him at the park. the bowling ball leaves the collision with a velocity of 1.44 m/s traveling in the same direction as the beach ball. calculate the speed of the beach ball.

Answer 1

4.03 m/s

Step-by-step explanation:

The law of conservation of linear momentum dictates that the sum of initial and final momentum should be equal. Momentum is the product of mass and velocity expressed as p=mv.

For this case, the equation would be

`m_a u_a +m_j u_j=m_a v_a +m_j v_j`

Where m represent mass, u and v represent initial and final velocities respectively while subscripts a and j represent Abigail's and Josh's ball respectively

Given info

Mass of Abigail's ball= 8.12 kg

Mass of Josh's ball= 524 g= 0.524 Kg

Initial velocity of Abigail's ball= 1.7 m/s

Initially velocity of Josh's ball= 0 m/s since it is sitting next to Josh to mean its stationery

Final velocity of Abigail's ball= 1.44 m/s

Final velocity of Josh's ball= unknown

Substituting the above given figures into the initial equation then

`8.12*1.7+(0.524*0)=8.12*1.44+(0.524v_j)\\v_j=4.0290076335877 m/s\approx 4.03 m/s`