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Two submersibles, one red and one blue, started rising toward the surface at the same time. They each rose at a constant speed.

The red submersible started rising from an altitude of 808080 meters below the surface. After 303030 seconds, it was 606060 meters below the surface.
The following equation gives the altitude (in meters relative to the surface) of the blue submersible as a function of time (in seconds).
A =-90+0.6tA=−90+0.6tA, equals, minus, 90, plus, 0, point, 6, t
Which submersible started rising from a higher altitude?

1 Answer

1 vote

Answer: The red submersible started from a higher altitude and the red submersible rose faster.

Explanation:

User Dnickels
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