![\sf\large\underline{\star Given:-}](https://img.qammunity.org/2023/formulas/mathematics/college/n5lt40risi18s22rdyb1wga5nzqp1he9mg.png)
Radius(r) of cone =
![\sf\pink{6cm.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y1mzcnhk1o5ohyhxe9tc0jc24h64nsk2cj.png)
Height(h) of Cone =
![\sf\pink{8cm.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/m66wyshwmjf76zyi2aqdt91a5q2hbhl6rw.png)
Slant height(l) of cone =
![\sf\pink{10cm}](https://img.qammunity.org/2023/formulas/mathematics/high-school/42sac4loa1v5tj2nhfakmonckv8wh9wr24.png)
![\sf\large\underline{\star To \: Find:-}](https://img.qammunity.org/2023/formulas/mathematics/college/dip3ofjnyddpprgp2fxqcri5rzw0vgt8fe.png)
Length of paper needed to make a cone with above given dimensions (i.e, curved surface area of cone).
![\sf\large\underline{\star Solution:-}](https://img.qammunity.org/2023/formulas/mathematics/college/2gnmtspajxgkxedqt3e9v21lktra1fey0z.png)
As we know that,
Curved surface area of cone =
![\sf\blue{πrl}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8os81xowa5axl6wkg0wkfyqie65dtrbt3y.png)
On substituting the value of radius(r) and slant height(l) in this formula we get,
![\sf{=\: (22)/(7)×6×10}](https://img.qammunity.org/2023/formulas/mathematics/high-school/d66imaxm39wvkfsj9crkr9kwgoi99use7s.png)
![\sf{=\: (22)/(7)×60}](https://img.qammunity.org/2023/formulas/mathematics/high-school/9ffu22wr61pcqx9pxq3osakb2nufmutlas.png)
![\sf{=\: (1320)/(7)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/oquvkkif5gpumamwyws0lzd6xtnin8n1w7.png)
![\sf{=\: 188.57 cm^2.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/bzegpw37usj47ylkasttdpaxnxajkzllvc.png)
Therefore,
paper is needed to make a cone of given dimensions.
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Hope it helps:)