Question

Use the following equation to answer questions 2 and 3. (Use the mole ratio for these problems only!)

3NOLaTeX: _22+ HLaTeX: _22O --> 2HNOLaTeX: _33 + NO

2. How many moles of NOLaTeX: _22are required to produce 3.56 mol of HNOLaTeX: _33?

3. How many moles of water react with 2.5 mol of NOLaTeX: _22?

Answer 1

5.34 moles of
`NO_2` are required to produce 3.56 mol of
`HNO_3`.

0.83 moles of water react with 2.5 moles of
`NO_2`.

Step-by-step explanation:

i)
`3NO_2+H_2O\rightarrow 2HNO_3+NO`

Moles of
`HNO_3` we want to produce = 3.56 moles

According to reaction, 2 moles of
`HNO_3` are obtained from 3 moles of
`NO_2`

Then 3.56 moles of
`HNO_3` will be obtained from :

`(3)/(2)* 3.56 mol=5.34 mol` of
`HNO_3`

5.34 moles of
`NO_2` are required to produce 3.56 mol of
`HNO_3`.

ii)

Moles of
`NO_2` = 2.5 moles

According to reaction,3 moles of
`NO_2` reacts with 1 mole of
`H_2O`,then 2.5 moles of
`NO_2` will react with :

`(1)/(3)* 2.5 mol=0.83 mol` of
`H_2O`

0.83 moles of water react with 2.5 moles of
`NO_2`.