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To play Multi-3, contestants spin the pointer of a wheel with ten equal sections, numbered 0–9. To win, the pointer must land on a number that is less than 3. Leo uses a random number generator to represent 50 trials of two contestants’ games.

4–4, 4–5, 2–2, 1–2, 3–4, 0–6, 1–8, 9–6, 5–6, 0–3, 6–7, 4–7, 3–5, 6–7, 3–8, 3–4, 8–4,
1–4, 6–0, 6–3, 2–9, 1–9, 0–2, 3–5, 6–7, 3–5, 9–2, 6–4, 7–3, 5–0, 2–5, 8–6, 6–3, 8–0,
8–2, 4–9, 4–8, 5–9, 7–9, 9–1, 5–8, 5–3, 1–5, 4–0, 6–7, 7–4, 2–9, 9–5, 1–4, 8–8

The numbers 0, 1, and 2 represent a win and the remaining numbers represent a loss. Based on the simulation results, what is the probability that both players will win Multi-3? Explain.

User Elyograg
by
4.3k points

2 Answers

4 votes

Answer:

the person above me is correct...

Explanation:

User Logan Besecker
by
3.9k points
3 votes

Answer:

3/50

Explanation:

3 / 50; Sample answer: There are three favorable

outcomes where both players win out of 50

trials: 22, 12, and 02.

User KonstantinK
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4.4k points