Answer:
a) The rate of change brightness after 't' years

b) The rate of increase after five years

Explanation:
a) Given B(t) = 5.0+0.55sin(
.....(1)
The rate of change of the brightness after 't' days that is

now differentiating equation (1) with respective to 't'
{ using d/dx(sin x) =cos x}

b) The rate of increase after five days
substitute t = 5 in equation dB/d t

after calculation
