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A desk manufacturer claims that the average time it takes to assemble a desk is 90 minutes with a standard deviation of 32 minutes. Suppose a random sample of 64 desk buyers is taken and time to assemble recorded. The standard deviation of the sample mean is ______ minutes.

User Siur
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1 Answer

2 votes

Answer:

The standard deviation of the sample mean is 4 minutes

Explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
\mu and standard deviation
\sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
\mu and standard deviation
s = (\sigma)/(√(n)).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

The standard deviation of the population is 32.

Sample of 64.

So


s = (32)/(√(64)) = 4

The standard deviation of the sample mean is 4 minutes

User TylerP
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