Question

Iron oxide and hydrogen react to form iron and water in the following chemical equation:

Fe2O3 + 3H2 ---------- 2Fe + 3H20
How many grams of iron oxide ( Fe2O3) are needed to create 172 grams of iron (Fe)?
245.9 g Fe2O3
86g Fe2O3
30.07g Fe203
55.85g Fe2O3

Answer 1

The answer to your question is 245.9 g of Fe₂O₃

Step-by-step explanation:

Data

grams of Fe₂O₃ = ?

grams of Fe = 172 g

Balanced chemical reaction

Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O

Process

1.- Calculate the molar mass of of Iron Oxide and Iron

Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g

2Fe = 2 x 56 = 112 g

2.- Use proportions and cross multiplication to solve this problem

160 g of Fe₂O₃ --------------- 112 g of Fe

x ---------------- 172 g of Fe

x = (172 x 160)/112

x = 27520/112

x = 245.9 g of Fe₂O₃