Question

A 3.90L sample of gas at STP is cooled to -55oC at 808mmHg. What is the new volume?

Answer 1

3.72L

Step-by-step explanation:

Given parameters:

Initial volume V₁ = 3.9L

Condition = STP

Final temperature T₂ = -550°C

Final pressure P₂ = 880mmHg

Unknown:

Final volume V₂ = ?

Solution.

At standard temperature and pressure(STP), the:

Pressure = 1atm = 760mmHg

Temperature = 273K

Therefore, P₁ = 760mmHg

T₁ = 273K

The general gas law, is best to solve this problem. It is mathematically given as:

`(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )`

Let us take the units to the appropriate one;

-550°C = 273 + (-550) = -277K

Input the variables;

`(760 x 3.9)/(273) = (808 x V_(2) )/(-277)`

V₂ = 3.72L