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Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and the price of the sugar increased by 20% and the same quantity of tea and sugar cost rupees 48.30. Find their prices in January

2 Answers

5 votes

Answer:

x = 15 rupees by kg ( price of tea)

y = 3 rupees by kg ( price of sugar)

Explanation:

Let call " x " the price of kg of tea and " y " the price of kg of sugar, in january of 1997,

then according to problem statement

2*x + 3*y = 39 (1)

But in march prices increased

tea by 25% that means its price in march will be 1.25*x, and the price of sugar will be 1.20*y, finally buying the same quantities now cost 48.30 rupees, then

2* ( 1.25*x ) + 3 * ( 1.20*y) = 48.30

2,50*x + 3.60*y = 48.30 (2)

Equations (1) and (2) are a two equation system, we need to solve for x and y

From equation (1) we have y = ( 39 - 2*x ) / 3

Plugging that value in equation (2)

2,50*x + 3.60* [ ( 39 - 2*x ) / 3] = 48.30

2,50*x + ( 140,40 - 7,20*x ) /3 = 48.30

7.50*x + 140,40 - 7,20*x = 144,90

0,30*x = 4.50

x = 4.50/0.30

x = 15 rupees

and y = ( 39 - 2*x ) / 3 ⇒ y = ( 39 - 2*15 ) / 3

y = ( 39 - 30 )/3

y = 3 rupees

User Worbel
by
6.3k points
2 votes

Answer: tea = 15 rupees per kg

sugar= 3 rupees per kg

Explanation:

Hi, to answer this question we have to write a system of equations with the information given:

"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "

2(t1.25)+3(s1.2) = 48.30 (b)

  • Solving for t in (b)

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • Replacing the value of t in (b)

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • Replacing the value of s in (a)

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

User Hamzah
by
5.6k points