Question

A circuit has a 2Ω resistor in series with a 4Ω resistor. What is the total resistance of the circuit?

Answer 1

• Total resistance of the circuit is 6Ω

Explaination :

The circuit is of series which has a resistor of 2Ω and 4Ω respectively.

As we know that, if n resistances joined in series are

Now,

• 
  `\sf{R_1 \: = 2Ω}`
• 
  `\sf{R_2 \: = 4Ω}`

Putting the values in it,

`\implies \: \sf{R_s \: = \: 2Ω \: + \: 4Ω}`

`\implies \: \bf{R_s \: = \: 6Ω}`

`\underline{\bf{ \therefore Total \: resistance \: of \: the \: circuit \: is \: 6Ω }}`

Answer 2

Answer: 6Ω

Step-by-step explanation:

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

R1 = 2Ω

R2 = 4Ω

Rtotal = ?

Rtotal = 2Ω + 4Ω

Rtotal = 6Ω

Thus, the total resistance of the circuit is 6Ω