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Student reacts with a piece of copper with a silver nitrate solution in a single replacement reaction. Write and balance the equation for this reaction.

User KeitelDOG
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Answer:

Cu(s) + 2AgNO₃(aq) → 2Ag(s) + Cu(NO₃)₂ (aq)

Step-by-step explanation:

Reactants: Cu(s), AgNO₃(aq)

This is a redox reaction, where the Ag and the Cu change the oxidation state

Ag, from +1 to 0 → reduction

Cu, from 0 to +2 → oxidation

Ag⁺ + 1e⁻ → Ag Reduction gains an electron

Cu → Cu²⁺ + 2e⁻ Oxidation releases 2 electrons

We multiply the half reactions:

(Ag⁺ + 1e⁻ → Ag) . 2 = 2Ag⁺ + 2e⁻ → 2Ag

(Cu → Cu²⁺ + 2e⁻) . 1 = Cu → Cu²⁺ + 2e⁻

We sum both reaction, so we cancel the e⁻:

2Ag⁺ + 2e⁻ + Cu → 2Ag + Cu²⁺ + 2e⁻

We add the other ions, to get the balanced equation:

Cu(s) + 2AgNO₃(aq) → 2Ag(s) + Cu(NO₃)₂ (aq)

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