48,724 views
15 votes
15 votes
A horse-drawn carriage tour company has found that the number of people that take their tour depends on the price charged per customer. The more the company charges for a tour, the fewer people decide to take the tour.

The function c(x)=50+5x represents price charged per customer where x is the number of $5 increases they charge over a rate of $50 per person.

The function p(x)=100−2x represents the number of customers expected for the day, where x is the number of $5 increases they charge over a rate of $50 per person.



What does (p⋅c)(2) mean about the horse-drawn carriage tour company?




The horse-drawn carriage tour company can expect to take in $3760 when the charge per customer is $40.

The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $40.

The horse-drawn carriage tour company can expect to take in $3760 when the charge per customer is $60.

A horse-drawn carriage tour company has found that the number of people that take-example-1
User Spencer Hall
by
2.9k points

2 Answers

16 votes
16 votes

Answer:

The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

Explanation:

A horse-drawn carriage tour company has found that the number of people that take-example-1
User Seraf
by
3.2k points
24 votes
24 votes

Answer:

B. The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

Explanation:

We have,

The function representing the price charged by the customers is .

The function representing the number of customers is .

Then, the product of the functions is given by,

Substituting x = 2 in the above product gives,

Also, the charge per customer when x = 2 is,

Hence, the product (p-c)(2) represents,

B. The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

User BrianScottK
by
2.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.