122k views
4 votes
Find the vertex of y = x^2+ 2x + 8

User Ambie
by
8.4k points

2 Answers

4 votes

Answer:

The vertex of the quadratic function is (-1,7).

Explanation:

The way to find the vertex is by first finding the AOS, the acronym for the "axis of symmetry".

The formula for the AOS is -B/2A, where B is the variable with "x" and A is the variable with "x^2" in the standard quadratic formula ax^2 + bx + c.

In the given quadratic equation, B would equal 2 and A would equal 1.

So now the next step is to substitute.

-2/2 * 1.

2 * 1 = 2. -2/2 = -1.

So -1 is the x-coordinate of the vertex.

Now let's find the y-coordinate.

We can find the y-coordinate by substituting -1 into the x-values of the equation.

-1^2 + 2 * -1 + 8.

Follow the rules of PEMDAS to get the correct answer.

First, simplify the exponent -1^2. The result is the same as -1 * -1, which is 1.

Next, simplify 2 * -1. The result is -2.

Then, add 1 and -2. The answer will be -1.

Finally, add -1 and 8 to get the y-coordinate 7.

The ordered pair of the vertex is (-1,7).

Hope this helps!

User Glguy
by
8.8k points
3 votes

Answer:

the vertex is : (-1 , 7)

Explanation:

hello :

y = x²+ 2x + 8

y= (x²+2x+1) +7

y= (x+1)²+7 ....vertex form when the vertex is : (-1 , 7)

User Rebeling
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories