122k views
4 votes
Find the vertex of y = x^2+ 2x + 8

User Ambie
by
6.1k points

2 Answers

4 votes

Answer:

The vertex of the quadratic function is (-1,7).

Explanation:

The way to find the vertex is by first finding the AOS, the acronym for the "axis of symmetry".

The formula for the AOS is -B/2A, where B is the variable with "x" and A is the variable with "x^2" in the standard quadratic formula ax^2 + bx + c.

In the given quadratic equation, B would equal 2 and A would equal 1.

So now the next step is to substitute.

-2/2 * 1.

2 * 1 = 2. -2/2 = -1.

So -1 is the x-coordinate of the vertex.

Now let's find the y-coordinate.

We can find the y-coordinate by substituting -1 into the x-values of the equation.

-1^2 + 2 * -1 + 8.

Follow the rules of PEMDAS to get the correct answer.

First, simplify the exponent -1^2. The result is the same as -1 * -1, which is 1.

Next, simplify 2 * -1. The result is -2.

Then, add 1 and -2. The answer will be -1.

Finally, add -1 and 8 to get the y-coordinate 7.

The ordered pair of the vertex is (-1,7).

Hope this helps!

User Glguy
by
6.4k points
3 votes

Answer:

the vertex is : (-1 , 7)

Explanation:

hello :

y = x²+ 2x + 8

y= (x²+2x+1) +7

y= (x+1)²+7 ....vertex form when the vertex is : (-1 , 7)

User Rebeling
by
6.4k points