Question

If the [H+] is 3.5x10-4, what is the [OH-]?

Answer 1

2.90 x 10⁻¹¹moldm⁻³

Step-by-step explanation:

Given parameters:

[H⁺] = 3.5 x 10⁻⁴mol/dm³

Unknown

[OH⁻] = ?

Solution;

The ionic product of water can be used to solve this problem. It has been experimentally determined to be 1 x 10⁻¹⁴mol² dm⁻⁶

[H⁺] [OH⁻] = 1 x 10⁻¹⁴

Therefore;

[OH⁻] =
`(1 x 10^(-14) )/(H)` =
`(1 x 10^(-14) )/(3.5 x 10^(-4) )` = 0.29 x 10⁻¹⁰moldm⁻³

= 2.90 x 10⁻¹¹moldm⁻³