Answer:
Using the formula ∆E = Ein - Eout
Qin + Win - Wout =∆U
Where the boundary work is defined as Wout =RTinv2/v1
Wout=0.287 ×290×In3
=91.4kj/kg
Now qin = 91.4 - 75 =16.4kj/kg
Heat transfered is 16.4kj/kg.
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