Tan A(secA-cosA)/sinA

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Reigo Hein · Answer 1 · 2021-03-12T02:14:54+0000

Answer:

tan A(secA-cosA)/sinA = tan²A

Explanation:

tanA (secA - cosA) / sinA = (SinA / CosA) (secA - cosA) / sinA

= (1 / CosA) (1 / CosA - CosA) = 1 / Cos²A - 1 = (1 - Cos²A) / Cos²A

= sin²A / Cos²A

= tan²A