80.1k views
2 votes
Tan A(secA-cosA)/sinA

User Twigg
by
5.5k points

1 Answer

5 votes

Answer:

tan A(secA-cosA)/sinA = tan²A

Explanation:

tanA (secA - cosA) / sinA = (SinA / CosA) (secA - cosA) / sinA

= (1 / CosA) (1 / CosA - CosA) = 1 / Cos²A - 1 = (1 - Cos²A) / Cos²A

= sin²A / Cos²A

= tan²A

User Reigo Hein
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.