Answer:
a= 1.15 m/s²; when coming down
a = 0 m/s² ; when maintaining a constant speed
Step-by-step explanation:
Assume the acceleration is positive in F = ma for all cases
But from the question we are told that the elevator is moving down (ma is negative since a is in the – negative direction)
∑ F = ma
T - mg = - ma because it is coming down
T = mg - ma
ma = mg - T
a =

=

a= 1.15 m/s²