Question

How far will 20 N of force stretch a spring with a spring constant of 140 N/m?

Answer 1

0.143 m

Step-by-step explanation:

The relationship between force applied on a string and stretching of the spring is given by Hooke's law:

`F=kx`

where

F is the force exerted on the spring

k is the spring constant of the spring

x is the stretching of the spring from its equilibrium position

In this problem, we have:

F = 20 N is the force applied on the spring

k = 140 N/m is the spring constant

Solving for x, we find how far the spring will stretch:

`x=(F)/(k)=(20)/(140)=0.143 m`