Find m v I need help with these two questions

Question

asked Oct 14, 2023 169k views

1 Answer

AMagyar · Answer 1 · 2023-10-18T20:14:19+0000

Answer:

15)

ABCD is quadrilateral

∠MBC+∠ABC=180°

∠ABC =
$\tt 180-71=109^o$

The sum of all angles of quadrilateral = 360°

$\tt 10x+6+12x-2+8x-1+109=360^o$

$\tt 31x+112=360$

$\tt 31x+112-112=360-112$ ( Subtract 112 from both sides)

$\tt 31x=248$ (Simplify)

$\tt \cfrac{31x}{31}=\cfrac{248}{31}$ (Divide both sides by 21)

$\tt x=8$

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16) Find m∠v

The polygon has 6 sides

Sum of angles:- (6-2)=180= 720°

so,

$\tt 90+9x-19+111+5x+8+128+7x+3=720$

$\tt 2x+321=720$

$\tt 21x+321-321=720-321$ ( Subtract 321 from both sides)

$\tt 21x=399$ (Simplify)

$\tt \cfrac{21x}{21}=\cfrac{399}{21}$ ( Divide both sides by 21)

$\tt x=19$

Therefore, m∠v=19

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