Question

Find m v I need help with these two questions

Answer 1

Step-by-step explanation:-

15)

ABCD is quadrilateral

∠MBC+∠ABC=180°

∠ABC =
`\tt 180-71=109^o`

The sum of all angles of quadrilateral = 360°

`\tt 10x+6+12x-2+8x-1+109=360^o`

`\tt 31x+112=360`

`\tt 31x+112-112=360-112` ( Subtract 112 from both sides)

`\tt 31x=248` (Simplify)

`\tt \cfrac{31x}{31}=\cfrac{248}{31}` (Divide both sides by 21)

`\tt x=8`

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16) Find m∠v

The polygon has 6 sides

Sum of angles:- (6-2)=180= 720°

so,

`\tt 90+9x-19+111+5x+8+128+7x+3=720`

`\tt 2x+321=720`

`\tt 21x+321-321=720-321` ( Subtract 321 from both sides)

`\tt 21x=399` (Simplify)

`\tt \cfrac{21x}{21}=\cfrac{399}{21}` ( Divide both sides by 21)

`\tt x=19`

Therefore, m∠v=19

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