176k views
0 votes
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) an = 7n 1 + 8n lim n→[infinity] an = Incorrect:

User Jadli
by
7.8k points

1 Answer

2 votes

Answer:

The sequence diverges

Explanation:

Given the sequence:


a_n=7n(1+8n)=7n+56n^2

Let's use the zero test which states:


\Sigma a_n\\Diverges\hspace{3}if\hspace{3} \lim_(n \to \infty) a_n \\eq0

So, let's find the limit:


\lim_(n \to \infty) 7n+56n^2= \lim_(n \to \infty) 7n + \lim_(n \to \infty) 56n^2

For the first limit:


\lim_(n \to \infty) 7n= 7 \lim_(n \to \infty) n=7* \infty=\infty

For the second limit:


\lim_(n \to \infty) 56n^2=56 \lim_(n \to \infty) n^2 =56(\infty)^2=\infty

So:


\lim_(n \to \infty) 7n+56n^2=\infty +\infty=\infty

Therefore, the sequence diverges

User Valenok
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories