Question

What is the factorization of the polynomial
2x^2+28x+98

Answer 1

Option B.
`2(x+7)(x+7)` is the factorization of the polynomial
`2x^(2) + 28x+98.`

Explanation:

Step 1:

To determine which of the following options is the factor for the polynomial we can expand the given options and see which matches the given polynomial
`2x^(2) + 28x+98.`

So we expand the four given options.

Step 2:

Option A.
`(2x+7)(x+7) = 2x^(2) +14x + 7x + 49 = 2x^(2) +21x+49.`

Option B.
`2(x+7)(x+7) = 2 (x^(2) +14x+49) = 2x^(2) + 28x + 98.`

Option C.
`(x+7)(x+2) = x^(2) +2x+7x+14= x^(2) +9x+14.`

Option D.
`(x+7)(x+14)= x^(2) +14x + 7x + 98 = x^(2) +21x+98.`

Only option B matches the given polynomial
`2x^(2) + 28x+98.` So option B is the factorization of the polynomial
`2x^(2) + 28x+98.`