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What is the factorization of the polynomial
2x^2+28x+98

What is the factorization of the polynomial 2x^2+28x+98-example-1

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Option B.
2(x+7)(x+7) is the factorization of the polynomial
2x^(2) + 28x+98.

Explanation:

Step 1:

To determine which of the following options is the factor for the polynomial we can expand the given options and see which matches the given polynomial
2x^(2) + 28x+98.

So we expand the four given options.

Step 2:

Option A.
(2x+7)(x+7) = 2x^(2) +14x + 7x + 49 = 2x^(2) +21x+49.

Option B.
2(x+7)(x+7) = 2 (x^(2) +14x+49) = 2x^(2) + 28x + 98.

Option C.
(x+7)(x+2) = x^(2) +2x+7x+14= x^(2) +9x+14.

Option D.
(x+7)(x+14)= x^(2) +14x + 7x + 98 = x^(2) +21x+98.

Only option B matches the given polynomial
2x^(2) + 28x+98. So option B is the factorization of the polynomial
2x^(2) + 28x+98.

User Jaynie
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