Answer:
a)59.30m
b)71.53m
Explanation:
so from my poor diagram
SOHCAHTOA
IN A WE USE TAN
Tan 56=opposite/40
tan 56=1.4827*40
=59.30
in b the distance from the top of the cliff to the object is the hypotenuse
(59.30)
59.30²+40²=5116.49
√5116,49
=71.53 m
i hope it does help if you dont understand any point pliz ask