Question

Trigonometry

Trigonometric Equations

0 ≤ x ≤ 2π, solve the equation 2 sin x cos x = sin x

Answer 1

x = 0, π/3, π, 5π/3, 2π

Explanation:

2sinxcosx = sinx

2sinxcosx - sinx = 0

sinx(2cosx - 1) = 0

sinx = 0, 2cosx-1 = 0

sinx = 0

x = 0, π, 2π

cosx = ½

basic angle = π/3

x = π/3, 2π - π/3 = 5π/3

x = 0, π/3, π, 5π/3, 2π