495,800 views
29 votes
29 votes
Help please!

Betty is 5 more than 3 times Jadyn's age. Betty is 41 old.
Write and solve an equation to find Jadyn's age, x

Equation:

Solution: x=

Jadyn is( ) years old.

User Gentry
by
3.1k points

2 Answers

12 votes
12 votes

Answer:

12 years old

Explanation:

3x+5=41

3 times a number and 5 more

'more' usually means adding

41-5 =36

36/3 =12

User Davide ND
by
2.8k points
4 votes
4 votes

Answer:

Equation: 41 = 3x + 5

x = 12

Explanation:

Hello!

Betty is 5 more than 3 times Jadyn's age. Since Jadyn's age is unknown, we'll call that unknown variable x.

Betty is 5 more than 3 times x. Betty is also 41 years old.

Equation: 41 = 3x + 5

Now we have to solve for x

Solve for x:

  • 41 = 3x + 5
  • 36 = 3x
  • x = 12

Jadyn is 12 years old.

User Andreas Siegel
by
2.9k points