Question

A capacitor is connected across an ac source. suppose the frequency of the source is doubled. what happens to the capacitive reactance of the capacitor?.

Answer 1

Step-by-step explanation:

The capacitive reactance of the capacitor is determined by
`X_(C)=(1)/(\omega C)`

When
`f'=2f \rightarrow \omega' =2\omega`

and
`X_(C)'=(1)/(2)X_(C)`

(The capacitive reactance will be reduced into 1/2 times of the previous capacitive reactance)