Question

A line has a slope of 1and passes through the point

(6, 3) What
is its equation in
slope -intercept
form?

Answer 1

y=x-3

Explanation:

First, you would need to put the information into point-slope form. y-y1=m(x-x1) using the (6,3) as (x1,y1).

It woud look like this: y-3= 1(x-6).

You would get rid of the parenthesis. y-3=x-6.

After this step, you would add 3 to both sides.

This would result in: y=x-3.

Answer 2

`\huge\boxed{y=x-3}`

Start with point-slope form, where
`m` is the slope and
`(x_1, y_1)` is a known point on the line.

`y-y_1=m(x-x_1)`

Substitute in the known values.

`y-3=1(x-6)`

Distribute the
`1` to the
`(x-6)`.

`y-3=x-6`

Add
`3` to both sides.

`\boxed{y=x-3}`