Answer:
For the velocity vector, we have
V(t) = dR
dt = (1, 2t, 3t
2
).
For the acceleration vector, we get
A =
dV
dt = (0, 2, 6t).
The velocity vector at t = 1 is
V(1) = (1, 2, 3).
The speed at t = 1 is
kV(1)k =
p
1
2 + 22 + 32 =
√
14.
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