Answer:
height of tower= 78.48 meters
Step-by-step explanation:
So here are your givens:
time(t)= 4 s.
initial velocity(u) = 0 m/s
acceleration due to gravity (g)= 9.81 m/s^2
distance(s)=s meters
using one of Newton's equation of motion ;
![s=ut+(1)/(2) gt^(2) \\s=0(4)+(1)/(2)(9.81)(4)^(2) \\s=(1)/(2) (9.81)(16)\\s=(156.96)/(2) \\s=78.48](https://img.qammunity.org/2021/formulas/physics/high-school/mcqh2wjofpg6bhue5sjryr71z0pouguasv.png)
height of the tower from the ground=total distance covered by bearing
height of tower= 78.48 meters