Answer:
where L is the length of the ramp
Step-by-step explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
![gsin\theta = 9.81 sin17^o = 2.87 m/s^2](https://img.qammunity.org/2021/formulas/physics/college/vxyitk2n67ddyt6p2b5d3z8lpr9f3y0bpw.png)
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
![v^2 - v_0^2 = 2a\Delta s](https://img.qammunity.org/2021/formulas/physics/college/ije8ryk0v89hzb6y9yjumoklzpz2qe2u41.png)
where v m/s is the final velocity,
= 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and
is the distance traveled:
![v^2 - 0 = 2*2.87*L](https://img.qammunity.org/2021/formulas/physics/college/hekj540tm8jxaduxf5007syq7bj2cg77v9.png)
![v = √(5.74L) = 2.4√(L)](https://img.qammunity.org/2021/formulas/physics/college/6e8oj2y2t9kbxweca4jawnm2my6jexjqkt.png)