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Two coils of wire are placed close together. Initially, a current of 1.80 A exists in one of the coils, but there is no current in the other. The current is then switched off in a time of 4.02 x 10-2 s. During this time, the average emf induced in the other coil is 4.38 V. What is the mutual inductance of the two-coil system?

User Christia
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2 Answers

6 votes

Answer:

M = 0.1H

Step-by-step explanation:

Please see attachment below.

Two coils of wire are placed close together. Initially, a current of 1.80 A exists-example-1
User Ulterior
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4.1k points
6 votes

Answer: the mutual inductance is - 0.0978H

Step-by-step explanation:

Detailed explanation and calculation is shown in the image below

Two coils of wire are placed close together. Initially, a current of 1.80 A exists-example-1
User Usergs
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4.4k points