Question

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 59.0 N at the surface of the earth. In this problem, use 9.80 m/s2 for the acceleration due to gravity on earth.

Answer 1

The weight of the watermelon on Jupiter's moon Io, calculated using the mass found from its weight on Earth (59.0 N) and Io's gravitational acceleration (1.81 m/s^2), would be approximately 10.88 N.

Step-by-step explanation:

The subject of your question is Physics, specifically focusing on the concept of gravitational acceleration on different celestial bodies. Let's find out how much a watermelon that weighs 59.0 N on Earth would weigh on Jupiter's moon Io. The weight of an object is calculated by multiplying the object's mass (m) by the acceleration due to gravity (g) at the location, W = m * g. On Earth, the acceleration due to gravity is 9.80 m/s2, while on Io, it is 1.81 m/s2.

To find the mass of the watermelon on Earth, we use the weight given (59.0 N) and Earth's gravitational pull: m = W / g = 59.0 N / 9.80 m/s2 = 6.02 kg.

Now, let's calculate the weight of the watermelon on Io using its mass and Io's gravitational acceleration: WIo = m * gIo = 6.02 kg * 1.81 m/s2 ≈ 10.88 N.

Thus, the watermelon would weigh approximately 10.88 N on the surface of Io.

Answer 2

The weight of watermelon on the surface of Jupiter = 10.9 N

Step-by-step explanation:

Weight of watermelon at the earth surface
`W_(earth)` = 59 N

Acceleration due to gravity at earth (
`g_(earth)` ) = 9.80
`(m)/(s^(2) )`

Mass of the object at earth surface M =
`(59)/(9.80)` = 6.02 kg

Acceleration due to gravity at Jupiter (
`g_(jupitor)` ) = 1.81
`(m)/(s^(2) )`

Weight of object at Jupiter's surface
`W_(jupiter)` = M ×
`g_(jupitor)`

⇒
`W_(jupiter)` = 6.02 × 1.81

⇒
`W_(jupiter)` = 10.9 N

This is the weight of watermelon on the surface of Jupiter.