Question

In a device like the one shown below, the cylinder is allowed to fall a distance of 300 m. As a result, the temperature of the water increases by 2.7°C. What would have been the increase in temperature if the cylinder were only allowed to fall 100 m?

Answer 1

Increase in the temperature of water would be 0.9 degree C

Step-by-step explanation:

I got it right

Answer 2

Increase in the temperature of water would be 0.9 degree C

Step-by-step explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

`U = mgh`

here we have

h = 300 m

now we can say

`Mc\Delta T = (m * 9.8 * 300)`

now if the cylinder falls from height h = 100 m

then we have

`Mc\Delta T' = (m * 9.8 * 100)`

now from above two equations

`(\Delta T')/(\Delta T) = (100)/(300)`

`\Delta T' = 2.7 * (1)/(3) = 0.9 Degree C`