Answer:
Amount of nitrogen consumed comes out to be 1050 g
Step-by-step explanation:
Number of moles of ammonia needed = 75 mole
The balanced reaction is shown below
![\textrm{N}_(2)\left ( g \right )+3\textrm{H}_(2)\left ( g \right )\rightarrow 2\textrm{NH}_(3)\left ( g \right )](https://img.qammunity.org/2021/formulas/chemistry/middle-school/wa0iuihozxfkqrmw8hmau4yaw69gbn2ytq.png)
1 mole of ammonia is needed for producing 2 mole ammonia according to the balanced reaction.
Number of moles of nitrogen needed for producing 75 mole ammonia = 37.5 mole
Molar mass of nitrogen gas = 28 g/mole
Amount of nitrogen gas needed =
![\left ( 37.5 \textrm{ mole}* 28 \textrm{ g/mol} \right ) = 1050 \textrm{ g}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/611v13xti9dr91temnup3yin1tsbix46hs.png)
Amount of nitrogen gas needed = 1050 g