Answer:
see answer below
Step-by-step explanation:
the equation is given by
k=ko* e^(-Q/RT)
then replacing the known values
k=1200 min⁻¹ e^[-8000 cal/mole/ (1.987 cal/mole K *T)]
then replacing values of T every 50 K from 100 to 500 K we get the series of values
![\left[\begin{array}{ccc}T&k\\100&3.924*10^(-15) min ^(-1) \\150&2.643*10^(-9) min ^(-1) \\200&2.17*10^(-6) min ^(-1) \\250&1.216*10^(-4) min ^(-1) \\300&1.781*10^(-3) min ^(-1) \\350&0.012 min ^(-1) \\400&0.051 min ^(-1) \\450&0.156 min ^(-1) \\500&0.382 min ^(-1) \end{array}\right]](https://img.qammunity.org/2021/formulas/computers-and-technology/college/d0ha035iukz4bxguampl34vqcoh5h4nknq.png)