Question

Chemical reaction rates are proportional to a rate constant, k, which changes with temperature according to the Arrhenius equation

k=koe^-Q/RT for :
Q=8000 cal/mole
R=1.987 cal/mole K
ko=1200 min-1
Find the value of k for Temperature from 100K to 500K, in 50 degree increments. Create a table of your results.

Answer 1

see answer below

Step-by-step explanation:

the equation is given by

k=ko* e^(-Q/RT)

then replacing the known values

k=1200 min⁻¹ e^[-8000 cal/mole/ (1.987 cal/mole K *T)]

then replacing values of T every 50 K from 100 to 500 K we get the series of values

`\left[\begin{array}{ccc}T&k\\100&3.924*10^(-15) min ^(-1) \\150&2.643*10^(-9) min ^(-1) \\200&2.17*10^(-6) min ^(-1) \\250&1.216*10^(-4) min ^(-1) \\300&1.781*10^(-3) min ^(-1) \\350&0.012 min ^(-1) \\400&0.051 min ^(-1) \\450&0.156 min ^(-1) \\500&0.382 min ^(-1) \end{array}\right]`