Answer:
The answer is g CO2 → mol CO2 → mol C6H12O6 → g C6H12O6
Step-by-step explanation:
The balanced equation (ignoring the state symbols) for this reaction is:
6 CO2 + 6 H2O → 6 O2 + C6H12O6
Which means 6 moles of CO2 produce 1 mole of C6H12O6
58.5g of CO2 would then produce 1.33 mole of C6H12O6
(∵mass ÷ molar mass of CO2)
⇒0.22159 moles of C6H12O6 was produced by 58.5g of CO2 during reaction
0.22159 moles of C6H12O6 has 39.9g of C6H12O6
(numb of mol × molar mass of C6H12O6 = mass)
Hence the solution map for finding the mass of glucose produced is:
g CO2 → mol CO2 → mol C6H12O6 → g C6H12O6